From 2947fdfe6a47a064bab8199ab1381ef4f1c3455b Mon Sep 17 00:00:00 2001
From: DJHills <20931105+DJHills@users.noreply.github.com>
Date: Fri, 9 Jan 2026 17:00:47 +0000
Subject: [PATCH] Point out that output of zip can be passed directly to dict

---
 .../DataStructures_II_Dictionaries.md                      | 7 +++++--
 1 file changed, 5 insertions(+), 2 deletions(-)

diff --git a/Python/Module2_EssentialsOfPython/DataStructures_II_Dictionaries.md b/Python/Module2_EssentialsOfPython/DataStructures_II_Dictionaries.md
index 77572dd4..64ad674e 100644
--- a/Python/Module2_EssentialsOfPython/DataStructures_II_Dictionaries.md
+++ b/Python/Module2_EssentialsOfPython/DataStructures_II_Dictionaries.md
@@ -446,10 +446,13 @@ for index in range(len(names)):
     grades[name] = value
 ```
 
-You should make use of the function [zip](https://www.pythonlikeyoumeanit.com/Module2_EssentialsOfPython/Itertools.html#zip) to pair the names and scores together in an iterable, and create the dictionary using a comprehension expression.
+You should make use of the function [zip](https://www.pythonlikeyoumeanit.com/Module2_EssentialsOfPython/Itertools.html#zip) to pair the names and scores together in an iterable, which can then be passed to `dict` or used in a comprehension expression.
 
 ```python
-# much better solution for creating `grades`
+# pass iterable output of `zip` straight to `dict` 
+grades = dict(zip(names, scores))
+
+# alternatively, iterate over output of `zip` using a comprehension expression
 grades = {student:value for student, value in zip(names, scores)}
 
 # updating Zoe's grade